`a.b = 0 rArr`Vectors a and b are orthogonal (b)IF ABCD be a cyclic quadrilateral, then `A + C = (pi)/(2)` and `B + D = (pi)/(2)` (c )`[abc] =a.(bxxc)`. If `u = q-r,r-p,p-q and v = log a^(2),log b^(2), log c^(2)` and a, b, c are `T_(p), T_(q), T_(s)` of a G.P. then angle between vectors u and v is ...
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The correct Answer is:
`theta = pi//2`
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