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The locus of the poles of normal chords ...

The locus of the poles of normal chords of the ellipse `x^(2)/a^(2) + y^(2)/b^(2) = 1`, is

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The correct Answer is:
`(a^6)/(x^2) + (b^6)/(y^2) = (a^2 - b^2)^2`
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