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If alpha is a root of 25"cos"^(2) theta+...

If `alpha` is a root of `25"cos"^(2) theta+ 5"cos" theta-12 = 0, (pi)/(2) lt alpha lt pi, " then sin"2 alpha` is equal to

A

`24/25`

B

`-24/25`

C

`13/18`

D

`-13/18`

Text Solution

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The correct Answer is:
B
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