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If x = X "cos" theta-Y "sin" theta, y = ...

If `x = X "cos" theta-Y "sin" theta, y = X "sin" theta + Y "cos" theta " and " x^(2) + 4xy + y^(2) =AX^(2) + BY^(2), 0 le theta le (pi)/(2), n in Z`, then

A

`theta = pi/6`

B

`theta = pi//4`

C

`A = 3`

D

`B = 1 `

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A, C, D
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