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The domain of the function sqrt(x^2 - [x...

The domain of the function `sqrt(x^2 - [x]^2)`, where [x] has the usual meaning, is

A

any +ive number

B

any-ive number

C

any +ive number or -ive integer

D

none

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The correct Answer is:
To find the domain of the function \( f(x) = \sqrt{x^2 - [x]^2} \), where \([x]\) is the greatest integer function (also known as the floor function), we need to ensure that the expression under the square root is non-negative. This means we need to solve the inequality: \[ x^2 - [x]^2 \geq 0 \] ### Step 1: Understanding the Greatest Integer Function The greatest integer function \([x]\) gives the largest integer less than or equal to \(x\). For any \(x\), we can express it as: \[ x = n + f \] where \(n = [x]\) (an integer) and \(f\) is the fractional part of \(x\) such that \(0 \leq f < 1\). ### Step 2: Expressing \(x^2\) and \([x]^2\) Substituting \(x\) into the inequality, we have: \[ x^2 = (n + f)^2 = n^2 + 2nf + f^2 \] And since \([x] = n\): \[ [x]^2 = n^2 \] ### Step 3: Setting Up the Inequality Now we can substitute these into the inequality: \[ n^2 + 2nf + f^2 - n^2 \geq 0 \] This simplifies to: \[ 2nf + f^2 \geq 0 \] ### Step 4: Analyzing the Inequality The expression \(2nf + f^2\) can be factored as: \[ f(2n + f) \geq 0 \] ### Step 5: Finding Conditions for \(f(2n + f) \geq 0\) 1. **Case 1: \(f = 0\)** If \(f = 0\), then \(x\) is an integer, and the inequality holds since \(0 \geq 0\). 2. **Case 2: \(f > 0\)** Here, \(0 < f < 1\). For the product \(f(2n + f)\) to be non-negative: - If \(n \geq 0\), \(2n + f > 0\) (always true). - If \(n < 0\), \(2n + f\) can be negative. We need \(2n + f \geq 0\), which gives \(f \geq -2n\). Since \(0 < f < 1\), we need: \[ -2n < 1 \implies n > -\frac{1}{2} \] Since \(n\) is an integer, this means \(n \geq 0\). ### Step 6: Conclusion on the Domain From the analysis: - **Positive integers** and **zero** satisfy the condition. - **Negative integers** do not satisfy the condition since \(f\) cannot be positive if \(n < 0\). Thus, the domain of the function \(f(x) = \sqrt{x^2 - [x]^2}\) is: \[ \text{Domain} = \{ x \in \mathbb{R} : x \text{ is a non-negative integer} \} \]
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