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Given that 10^(0.48) = x , 10^(0.70) =...

Given that `10^(0.48) = x , 10^(0.70) = y , and x^(z) = y^(2)` , then the value of z is close to

A

`1.45`

B

`1.88`

C

`2.9`

D

`3.7`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's start by rewriting the given equations and then manipulate them to find the value of \( z \). ### Step 1: Rewrite the given equations We have: 1. \( 10^{0.48} = x \) 2. \( 10^{0.70} = y \) 3. \( x^z = y^2 \) ### Step 2: Substitute the values of \( x \) and \( y \) Substituting the values of \( x \) and \( y \) into the equation \( x^z = y^2 \): \[ (10^{0.48})^z = (10^{0.70})^2 \] ### Step 3: Simplify the equation Using the property of exponents \( (a^m)^n = a^{m \cdot n} \), we can simplify both sides: \[ 10^{0.48z} = 10^{1.40} \] Here, \( (10^{0.70})^2 = 10^{0.70 \cdot 2} = 10^{1.40} \). ### Step 4: Set the exponents equal to each other Since the bases are the same, we can set the exponents equal to each other: \[ 0.48z = 1.40 \] ### Step 5: Solve for \( z \) Now, we can solve for \( z \): \[ z = \frac{1.40}{0.48} \] ### Step 6: Calculate the value of \( z \) Calculating the fraction: \[ z = \frac{1.40}{0.48} = \frac{140}{48} = \frac{35}{12} \] Now, we can convert \( \frac{35}{12} \) to a decimal: \[ \frac{35}{12} \approx 2.9167 \] So, \( z \) is approximately \( 2.92 \). ### Conclusion The value of \( z \) is close to \( 2.9 \). ---
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