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If x = at^(2) and y = 2 at then...

If ` x = at^(2) and y = 2 ` at then

A

`x^(2) = 4ay`

B

`y^(2) = 4ax`

C

` x^(2) + y^(2) = a^(2)`

D

`x^(2) - y^(2) = a^(2)`

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The correct Answer is:
To find the relationship between \( x \) and \( y \) given the equations \( x = at^2 \) and \( y = 2at \), we can follow these steps: ### Step 1: Write down the equations We have: \[ x = at^2 \] \[ y = 2at \] ### Step 2: Solve for \( a \) in terms of \( y \) From the equation \( y = 2at \), we can express \( a \) as: \[ a = \frac{y}{2t} \] ### Step 3: Substitute \( a \) into the equation for \( x \) Now, substitute \( a \) into the equation for \( x \): \[ x = a t^2 = \left(\frac{y}{2t}\right) t^2 \] This simplifies to: \[ x = \frac{y t}{2} \] ### Step 4: Express \( t \) in terms of \( y \) and \( x \) Rearranging the equation \( x = \frac{y t}{2} \) gives: \[ t = \frac{2x}{y} \] ### Step 5: Substitute \( t \) back into the equation for \( y \) Now substitute \( t \) back into the equation for \( y \): \[ y = 2a t = 2a \left(\frac{2x}{y}\right) \] Substituting \( a = \frac{y}{2t} \) gives: \[ y = 2 \left(\frac{y}{2 \left(\frac{2x}{y}\right)}\right) \left(\frac{2x}{y}\right) \] This simplifies to: \[ y^2 = 4ax \] ### Step 6: Final relationship Thus, we have the final relationship: \[ y^2 = 4ax \]
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