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If (x)/( y) = (3)/( 4) , then value of ...

If ` (x)/( y) = (3)/( 4)` , then value of `(6)/(7) + (y - x)/( y + x)` is

A

1

B

`(2)/(7)`

C

`(3)/(7)`

D

`1(3)/(7)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we start with the given equation and work towards finding the required value. **Step 1: Understand the given ratio.** We are given that \( \frac{x}{y} = \frac{3}{4} \). This means that \( x \) and \( y \) are in the ratio of 3 to 4. **Step 2: Express \( x \) and \( y \) in terms of a common variable.** Let’s introduce a variable \( k \) such that: - \( x = 3k \) - \( y = 4k \) **Step 3: Substitute \( x \) and \( y \) into the expression.** We need to find the value of: \[ \frac{6}{7} + \frac{y - x}{y + x} \] Substituting \( x \) and \( y \): \[ \frac{6}{7} + \frac{4k - 3k}{4k + 3k} \] **Step 4: Simplify the expression.** Now simplify the fraction: \[ \frac{4k - 3k}{4k + 3k} = \frac{k}{7k} = \frac{1}{7} \] **Step 5: Combine the two fractions.** Now we have: \[ \frac{6}{7} + \frac{1}{7} \] Since the denominators are the same, we can add the numerators: \[ \frac{6 + 1}{7} = \frac{7}{7} = 1 \] **Final Answer:** The value of \( \frac{6}{7} + \frac{y - x}{y + x} \) is \( 1 \). ---
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