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If 1 . 5 x = 0.04 y ,t hen the value of...

If ` 1 . 5 x = 0.04 y` ,t hen the value of ` ( y^(2) - x^(2))/( y^(2) + 2xy + x^(2)) ` is

A

A)`(730)/(77)`

B

B)`(73)/(77)`

C

C)`(73)/(770)`

D

D)`(74)/(77)`

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The correct Answer is:
To solve the equation \( 1.5x = 0.04y \) and find the value of \( \frac{y^2 - x^2}{y^2 + 2xy + x^2} \), we can follow these steps: ### Step 1: Find the relationship between \( x \) and \( y \) Starting from the equation: \[ 1.5x = 0.04y \] We can rearrange this to express \( \frac{x}{y} \): \[ \frac{x}{y} = \frac{0.04}{1.5} \] ### Step 2: Simplify the fraction To simplify \( \frac{0.04}{1.5} \), we can eliminate the decimal points: \[ \frac{0.04}{1.5} = \frac{4}{150} = \frac{2}{75} \] Thus, we have: \[ \frac{x}{y} = \frac{2}{75} \] ### Step 3: Assign values to \( x \) and \( y \) From \( \frac{x}{y} = \frac{2}{75} \), we can assign: \[ x = 2 \quad \text{and} \quad y = 75 \] ### Step 4: Substitute \( x \) and \( y \) into the expression Now we need to find the value of: \[ \frac{y^2 - x^2}{y^2 + 2xy + x^2} \] Calculating \( y^2 - x^2 \): \[ y^2 - x^2 = 75^2 - 2^2 = 5625 - 4 = 5621 \] Calculating \( y^2 + 2xy + x^2 \): \[ y^2 + 2xy + x^2 = 75^2 + 2 \cdot 75 \cdot 2 + 2^2 = 5625 + 300 + 4 = 5929 \] ### Step 5: Substitute the results into the expression Now substituting these values into the expression: \[ \frac{y^2 - x^2}{y^2 + 2xy + x^2} = \frac{5621}{5929} \] ### Step 6: Simplify the fraction Now we check if \( \frac{5621}{5929} \) can be simplified. Since there are no common factors, this fraction is already in its simplest form. ### Final Answer Thus, the value of \( \frac{y^2 - x^2}{y^2 + 2xy + x^2} \) is: \[ \frac{5621}{5929} \]
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