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If x - y = ( x + y)/(7) = (xy)/(4) the ...

If ` x - y = ( x + y)/(7) = (xy)/(4)` the numerical value of xy is

A

`(4)/(3)`

B

`(3)/(4)`

C

`(1)/(4)`

D

`(1)/(3)`

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The correct Answer is:
To solve the equation \( x - y = \frac{x + y}{7} = \frac{xy}{4} \), we can follow these steps: ### Step 1: Set the expressions equal to a variable Let \( k \) be the common value of the three expressions: \[ x - y = k, \quad \frac{x + y}{7} = k, \quad \frac{xy}{4} = k \] ### Step 2: Express \( x + y \) and \( xy \) in terms of \( k \) From the second equation, we can express \( x + y \): \[ x + y = 7k \] From the third equation, we can express \( xy \): \[ xy = 4k \] ### Step 3: Solve for \( x \) and \( y \) Now we have two equations: 1. \( x - y = k \) (Equation 1) 2. \( x + y = 7k \) (Equation 2) We can add these two equations to eliminate \( y \): \[ (x - y) + (x + y) = k + 7k \] This simplifies to: \[ 2x = 8k \implies x = 4k \] Now, substitute \( x \) back into Equation 1 to find \( y \): \[ 4k - y = k \implies y = 4k - k = 3k \] ### Step 4: Substitute \( x \) and \( y \) back into the expression for \( xy \) Now we can find \( xy \): \[ xy = (4k)(3k) = 12k^2 \] But we also know from our earlier step that \( xy = 4k \). So we set these equal: \[ 12k^2 = 4k \] ### Step 5: Solve for \( k \) Divide both sides by \( k \) (assuming \( k \neq 0 \)): \[ 12k = 4 \implies k = \frac{4}{12} = \frac{1}{3} \] ### Step 6: Find \( x \) and \( y \) Now substitute \( k \) back to find \( x \) and \( y \): \[ x = 4k = 4 \cdot \frac{1}{3} = \frac{4}{3} \] \[ y = 3k = 3 \cdot \frac{1}{3} = 1 \] ### Step 7: Calculate \( xy \) Now we can find \( xy \): \[ xy = \left(\frac{4}{3}\right)(1) = \frac{4}{3} \] Thus, the numerical value of \( xy \) is: \[ \boxed{\frac{4}{3}} \]
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