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If y ^(4) + (1)/( y^(4)) = 223 and y ...

If ` y ^(4) + (1)/( y^(4)) = 223 and y gt 1 ` then find the value of ` ( y^(2) + (1) /( y^(2)))` ?

A

15

B

14

C

14.86

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( y^4 + \frac{1}{y^4} = 223 \) and find the value of \( y^2 + \frac{1}{y^2} \), we can follow these steps: ### Step 1: Let \( x = y^2 + \frac{1}{y^2} \) We start by letting \( x = y^2 + \frac{1}{y^2} \). ### Step 2: Relate \( y^4 + \frac{1}{y^4} \) to \( x \) We know that: \[ y^4 + \frac{1}{y^4} = \left( y^2 + \frac{1}{y^2} \right)^2 - 2 \] This means: \[ y^4 + \frac{1}{y^4} = x^2 - 2 \] ### Step 3: Substitute into the original equation Now, we can substitute this into the original equation: \[ x^2 - 2 = 223 \] ### Step 4: Solve for \( x^2 \) Adding 2 to both sides gives us: \[ x^2 = 223 + 2 = 225 \] ### Step 5: Solve for \( x \) Taking the square root of both sides, we find: \[ x = \sqrt{225} = 15 \] ### Conclusion Thus, the value of \( y^2 + \frac{1}{y^2} \) is: \[ \boxed{15} \]
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