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If a^(2) + a + 1 = 0 then the value of...

If ` a^(2) + a + 1 = 0` then the value of ` a^(9)` is

A

2

B

3

C

1

D

0

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AI Generated Solution

The correct Answer is:
To solve the equation \( a^2 + a + 1 = 0 \) and find the value of \( a^9 \), we can follow these steps: ### Step 1: Solve for \( a^2 \) We start with the equation: \[ a^2 + a + 1 = 0 \] From this, we can express \( a^2 \) in terms of \( a \): \[ a^2 = -a - 1 \] ### Step 2: Find \( a^3 \) Next, we can find \( a^3 \) by multiplying both sides of the equation \( a^2 = -a - 1 \) by \( a \): \[ a^3 = a \cdot a^2 = a(-a - 1) = -a^2 - a \] Now, we substitute \( a^2 \) from Step 1: \[ a^3 = -(-a - 1) - a = a + 1 - a = 1 \] ### Step 3: Calculate \( a^6 \) Now that we have \( a^3 = 1 \), we can find \( a^6 \) by squaring \( a^3 \): \[ a^6 = (a^3)^2 = 1^2 = 1 \] ### Step 4: Calculate \( a^9 \) Finally, we can find \( a^9 \) by multiplying \( a^6 \) and \( a^3 \): \[ a^9 = a^6 \cdot a^3 = 1 \cdot 1 = 1 \] ### Conclusion Thus, the value of \( a^9 \) is: \[ \boxed{1} \]
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