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If 3 sqrt( a) + 3 sqrt( b) = 3 sqrt( c)...

If ` 3 sqrt( a) + 3 sqrt( b) = 3 sqrt( c)` , then the simplest value of ` ( a + b - c) ^(3) + 27` abc is

A

`-1`

B

3

C

`-3`

D

0

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The correct Answer is:
To solve the equation \( 3 \sqrt{a} + 3 \sqrt{b} = 3 \sqrt{c} \), we can simplify it step by step. ### Step 1: Simplify the equation First, we can divide the entire equation by 3: \[ \sqrt{a} + \sqrt{b} = \sqrt{c} \] ### Step 2: Cube both sides Next, we will cube both sides of the equation: \[ (\sqrt{a} + \sqrt{b})^3 = (\sqrt{c})^3 \] This simplifies to: \[ \sqrt{a}^3 + 3\sqrt{a}^2\sqrt{b} + 3\sqrt{a}\sqrt{b}^2 + \sqrt{b}^3 = c \] Since \(\sqrt{a}^3 = a\) and \(\sqrt{b}^3 = b\), we can rewrite the equation as: \[ a + b + 3\sqrt{ab}(\sqrt{a} + \sqrt{b}) = c \] But since \(\sqrt{a} + \sqrt{b} = \sqrt{c}\): \[ a + b + 3\sqrt{ab}\sqrt{c} = c \] ### Step 3: Rearranging the equation Now, we rearrange the equation to isolate \(c\): \[ a + b - c + 3\sqrt{ab}\sqrt{c} = 0 \] This implies: \[ a + b - c = -3\sqrt{ab}\sqrt{c} \] ### Step 4: Finding \( (a + b - c)^3 + 27abc \) Let \( x = a + b - c \). Then, we have: \[ x = -3\sqrt{ab}\sqrt{c} \] Cubing both sides gives: \[ x^3 = (-3\sqrt{ab}\sqrt{c})^3 = -27abc \] Thus: \[ x^3 + 27abc = 0 \] ### Step 5: Conclusion The simplest value of \( (a + b - c)^3 + 27abc \) is: \[ 0 \]
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