If the ordinate and abscissa of the point (k, 2 k - 1) be equal then the value of k is

Options

A. 0
B. `-1`
C. 1
D. `(1)/(2)`

Answer

To solve the problem, we need to find the value of \( k \) such that the ordinate (y-coordinate) and abscissa (x-coordinate) of the point \( (k, 2k - 1) \) are equal.

### Step-by-step solution:

1. **Identify the coordinates**: The point is given as \( (k, 2k - 1) \). Here, the abscissa (x-coordinate) is \( k \) and the ordinate (y-coordinate) is \( 2k - 1 \).

2. **Set the coordinates equal**: Since we want the ordinate and abscissa to be equal, we set up the equation:
\[ k = 2k - 1 \]

3. **Rearrange the equation**: To solve for \( k \), we can rearrange the equation by moving \( k \) to the right side:
\[ 0 = 2k - k - 1 \]
Simplifying this gives:
\[ 0 = k - 1 \]

4. **Solve for \( k \)**: Now, we can solve for \( k \):
\[ k = 1 \]

### Conclusion:
The value of \( k \) is \( 1 \).