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MODERN PUBLICATION-INVERSE-TRIGONOMETRIC FUNCTIONS-EXERCISE
- tan^-1 sqrt3 - sec^-1 (-2) is equal to :
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- Find the value of cos^-1(cos((3pi)/2))
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- Evaluate: tan^-1{sin(-pi/2)}
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- Evaluate : sin^-1[cos(sin^-1(sqrt3)/2)]
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- Find the value of sec(tan^-1 (y/2)) in terms of y.
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- Find the value of sin[2cot^-1(5/12)]
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- Which is greater tan 1 or tan^-1 1?
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- Evaluate : cos [sin^-1(1/4) + sec ^-14/3]
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- Find the value of the expression : sin(2tan^-1(1/3)) + cos(Tan^-1 2sqr...
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- Solve for x: sin^-1 x + sin^-1(1-x) = cos^-1x
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- find the value of x: cos(tan^-1x) = sin(cot^-1(3)/(4))
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- Find the solution of the equation: tan^-1x - cot^-1 x = tan^-1(1/sqrt3...
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- Show that : sec(cosec^-1x) = (|x|)/(sqrt(x^2-1)), for |x| > 1
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- Show that : cos(2 tan^-1 x) = (1-x^2)/(1+x^2)
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- Prove that : sin(tan^(-1)1) = 1/sqrt2
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- Prove that : cosec[tan^-1(-sqrt3)] = -2/sqrt3
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- Solve : 3 tan^-1(1/(2+sqrt3)) - tan^-1(1/x) = tan^-1(1/3)
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- Solve : sin^-1(5/x) + sin^-1(12/x) = pi/2
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- Show that sin^-1[sin(3pi)/4]ne (3pi)/4 . What is its value?
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- tan^-1[tan(5pi)/6] ne (5pi)/6, What is its value?
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- Prove that : tan^-1 x + cot^-1(x+1) = tan^-1(x^2 + x +1)
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