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MODERN PUBLICATION-INVERSE-TRIGONOMETRIC FUNCTIONS-EXERCISE
- Show that sin^-1[sin(3pi)/4]ne (3pi)/4 . What is its value?
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- tan^-1[tan(5pi)/6] ne (5pi)/6, What is its value?
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- Prove that : tan^-1 x + cot^-1(x+1) = tan^-1(x^2 + x +1)
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- Prove that : cot^-1 3 + cosec^-1 sqrt5 = pi/4
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- Prove that : sec^2 (tan^(-1)2) + cosec^2 (cot^(-1) 3) = 15
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- If sin^-1 x = y, then
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- tan^-1 sqrt3 - sec^-1 (-2) is equal to :
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- Find the values of each of the expressions cos^-1(cos((7pi)/6)) is e...
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- sin(pi/3 - sin^-1(-1/2)) is equal to
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- tan^-1sqrt3 - cot^-1(1-sqrt3) is equal to
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- sin(tan^-1x), |x|<1 is equal to :
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- If sin^-1(1-x) - 2sin^-1x = pi/2, then x is equal to :
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- tan^-1(x/y)-tan^-1((x-y)/(x+y)) is equal to :
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- The value of sin^(-1)(cos""(43pi)/(5)) is
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- The principal value of the expression cos^(-1)[cos(-680^(@))] is
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- The value of cot(sin^(-1)x) is
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- The domain of sin^(-1)2x is
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- The greatest and least values of (sin^-1 x)^2 + (cos^-1x)^2 are respec...
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- If sin^-1x = y, then:
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- Find the value of the following tan^-1(tan(3pi)/4)
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