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If alpha = 3 sin^(-1) (6/11) " and "be...

If ` alpha = 3 sin^(-1) (6/11) " and "beta = 3 cos^(-1) (4/9) `, where the inverse trigonometric functions take only the principal values, then the correct option (s) is /are

A

`cos beta gt 0`

B

`sin beta lt 0`

C

`cos(alpha + beta ) gt0`

D

`cosalpha lt 0`

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