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Let A = [[0,1],[0,0]] , show that (aI + ...

Let `A = [[0,1],[0,0]]` , show that `(aI + bA)^n = a^nI + na^(n-1) bA`, where I is the identity matrix of order 2 and`n in N`

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MODERN PUBLICATION-DETERMINANTS-EXERCISE
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  7. For a 2xx2 matrix, A = [a(ij)], whose elements are given by a(ij) = ...

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  8. If A is a square matrix such that A^2 = A, then write the value of (I+...

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