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If u = sin^-1(2x/(1+x)^2) and v = tan^-1...

If `u = sin^-1(2x/(1+x)^2) and v = tan^-1(2x/(1-x^2))`, the `du/dv` is

A

`1/2`

B

x

C

`(1-x^2)/(1+x^2)`

D

1

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