f(x)={((x^2-4)/(x-2),x!=2),(2k,x=2):} is...

`f(x)={((x^2-4)/(x-2),x!=2),(2k,x=2):}` is continuous at x=2 then k=

A

2

B

4

C

6

D

None of these

Verified by Experts

CONTINUITY AND DIFFERENTIABILITY
MODERN PUBLICATION|Exercise EXERCISE|588 Videos
APPLICATIONS OF THE INTEGRALS
MODERN PUBLICATION|Exercise EXERCISE|211 Videos
DETERMINANTS
MODERN PUBLICATION|Exercise EXERCISE|326 Videos

Similar Questions

Explore conceptually related problems

If f(x) = {:{((x^2-(a+2)x+a)/(x-2), x ne2),(2,x=2):} is continuous at x =2, then the value of a is

If f(x) = {((tan3x)/(x),,, x!=0,),(4k,,,x,=0):} is continuous at x=0' then K=

If f(x)={(2x+3,x,le1),(k,,x>):} is continuous at x=1 then k=

Find a if f(x)={((sqrt(5x+2)-sqrt(4x+4))/(x-2),x!=2),(a,x=2):} is continuous as x=2

If f(x)= {(kx^2,,x,<,2),(3,,x,ge,2):} is continuous at x = 2, then the value of 'k' is :

If f(x)={((x^(2)-25)/(x-5)" , "xne5),(k" , "x=5):} is continuous at x=5, then k is equal to:

If f(x) = {{:((x^(2)-(a+2)x+2a)/(x-2)",",x ne 2),(" "2",",x = 2):} is continuous at x = 2, then a is equal to

If f(x) = {:{((x^3+x^2-16x+20)/((x-2)^2), x ne2), (k, x =2):} is continuous at x =2, find the value of 'k'.

If f(x) = {((sin 5x)/(2x),,x,ne,0),(k,,x,=,0):} is continuous at x = 0 then value of k is :

Determine the constant k, so that the function f(x) = {{:((x^2- 9)/(x -3)"," ,x != 3),(k",", x = 3):} is continuous at x=3.