Show that sin^(p) thetacos^(q)thetaattai...

Show that `sin^(p) thetacos^(q)theta`attains a maximum when `theta=tan^-1sqrt((p/q))`

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APPLICATION OF DERIVATIVES
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Prove that : tan^2 theta -sin^2 theta =tan^2 theta sin^2 theta .

Prove that sin^6theta+cos^6theta=1-3sin^2thetacos^2theta .

Prove that sin^4theta+cos^4theta=1-2sin^2thetacos^2theta .

P=1/2 sin^2 theta+1/3 cos^2 theta , then :

If tan theta =p/q , show that : (p sin theta-q cos theta)/(p sin theta+q cos theta)= (p^2-q^2)/(p^2+q^2) .

The maximum value of sin theta cos theta is :

Prove that sin theta< theta< tan theta for theta in (0,pi/2) .

Statement I The maximum value of sin theta+costheta is 2. Statement II The maximum value of sin theta is 1 and that of cos theta is also 1.

Find sin 2 theta when sin theta + cos theta= 1 .

MODERN PUBLICATION-APPLICATION OF DERIVATIVES-EXERCISE

Show that sin^(p) thetacos^(q)thetaattains a maximum when theta=tan^-1...
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