If `veca =2hati+hatj-2hatk`, then evaluate `|veca|`.

If veca=2hati-6hatj-3hatk then |\veca| =

If veca=2hati+sqrt3hatj+3hatk and vecb=3hati+2hatj-2sqrt3hatk , then : evaluate (3veca-5vecb)xx(2veca-vecb) .

If veca=2hati+hatj+3hatk and vecb=3hati+5hatj-2hatk , then find |\vecaxxvecb| .

If veca=hati+hatj+hatk,hatb=hati-hatj+hatk,vecc=hati+2hatj-hatk , then find the value of |{:(veca.veca,veca.vecb,veca.vecc),(vecb.veca,vecb.vecb,vecb.vecc),(vecc.veca,vecc.vecb,vecc.vecc):}|

If veca = hati-hatj+hatk , vecb = 2hati-3hatj+hatk , then find |2vecaxxvecb|

If veca=3hati+2hatj+2hatk and vecb=hati+2hatj-2hatk , then find a unit vector which is perpendicular to both the vectors (veca-vecb) and (veca+vecb) .

If veca=2hati-hatj+hatk and vecb=2hatj-hatk then veca.vecb is equal to :

Consider the equation of the straight lines given by : L_1:vecr=(hati+2hatj+hatk)+lambda(hati-hatj+hatk) L_2:vecr=(2hati-hatj-hatk)+mu(2hati+hatj+2hatk) If veca_1=hati+2hatj+hatk, vecb_1=hati-hatj+hatk, veca_2=2hati-hatj-hatk, vecb_2=2hati+hatj+2hatk , then find : veca_2-veca_1

If veca=5hati+hatj-4hatk, vecb=2hati-3hatj+hatk and vecc=hati+3hatj-2hatk then find a unit vector parallel to the vector 2veca+vecb+3vecc .