Find the angle between the line `(x+1)/2 = y/3 = (z-3)/6` and the plane `10x+2y-11z = 3`

Find the angle between the lines (x+1)/(2)=(y)/(3)=(z-3)/(6) and the planes 3x+y+z=7 .

Find the angle between the line (x-2)/3=(y+1)/-1=(z-3)/-2 and the plane 3x+4y+z+5=0 .

Find the angle between the line x-1/3=3-y/-1=3z+1/6 and the plane 3x -5y + 2z = 10 .

Statement 1 : Let theta be the angle between the line (x-2)/(2)=(y-1)/(-3)= (z+2)/(-2) and the plane x+y-z=5 . Then theta= sin ^(-1)(1//sqrt(51)) . Statement 2 : The angle between a straight line and a plane is the complement of the angle between the line and the normal to the plane.

Find the angle between the given lines (x-1)/3=(3-y)/-1=(3z+1)/6 and plane 3x-5y+ 2z= 10.

If the angle theta between the line (x+1)/(1) = ( y-1)/(2) = (z-2)/(2) and the plane 2x-y+sqrt( lambda ) z + 4 =0 is such that sin theta = (1)/(3) then the value of lambda is

If the angle between the line x=(y-1)/(2)=(z-3)(lambda) and the plane x+2y+3z=4 is cos^(-1)(sqrt((5)/(14))) , then lambda equals

Find the point where the line (x+1)/2=(y+2)/3=(z+3)/4 meets the plane x+y+4z=6 .

Find the angle between the planes 2x-3y+4z=1 and -x+y=4 .

Find the projection of the line (x-1)/2=(y+1)/-1=(z-3)/4 in the plane x+2y+z-9=0 .