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The cartesian equation of a line is (x-5...

The cartesian equation of a line is `(x-5)/3 = (y+4)/7 = (z-6)/2`. Write its vector form.

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MODERN PUBLICATION-Three Dimensional Geometry-EXERCISE
  1. Find the equation of the line in vector and in cartesian form that pas...

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  2. Find the cartesian equation of the line which passes through the point...

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  3. The cartesian equation of a line is (x-5)/3 = (y+4)/7 = (z-6)/2. Write...

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  4. Find the vector and the cartesian equations of the lines that passes t...

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  5. Find the vector and the cartesian equations of the line that passes th...

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  6. Find the angle between the following pair of lines: vecr = 2hati-5hatj...

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  7. Find the angle between the following pair of lines: vecr = 3hati+hatj-...

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  8. Find the angle between the following pairs of lines : (x-2)/2=(y-1)/5=...

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  9. Find the angle between the lines x/2=y/2=z/1 and [x-5]/4=[y-2]/1=[z-3]...

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  10. Find the value of p so that the lines : l1:(1-x)/3=(7y-14)/(2p)=(z-3)/...

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  11. Show that the lines (x-5)/7 = (y+2)/-5 = z/1 and x/1 = y/2 = z/3 are p...

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  12. Find the shortest distance between the lines vecr = (hati + 2hatj+hatk...

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  13. Find the shortest distance between the lines ((x+1)/7=(y+1)/-6=(z+1)/1...

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  14. Find the shortest distance between the lines whose vector equations ar...

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  15. Find the shortest distance between the following lines whose vector eq...

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  16. In the following case, determine the direction cosines of the normal ...

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  17. In the following case, determine the direction cosines of the normal ...

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  18. In each of the following cases, determine the direction cosines of the...

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  19. In the following case, determine the direction cosines of the normal ...

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  20. Find the vector equation of a plane, which is at a distance of 7 units...

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