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underline()div4=-3...

`underline()div4=-3`

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underline()div1=-87

(-4)+[15+(-3)]=[-4+15]+underline()

Value of the ecpressioson [(60)div12]div(-5) is underline() .

In the following reaction, how is the rate of appearance of the underlined Product related to the rate of disappearance of the underlined reactant ? BrO_(3)^(ɵ)(aq) + 5underline(Br)^(ɵ)(aq) + 6H^(o+) (aq) rarr 3underline(Br_(2))(l) + 3H_(2)O(l)