A ball thrown up vertically returns to the thrower after 6 s.Find the maximum height it reached .

Explanation

By Second equation of motion,
`s = u t + (1)/(2) g t^(2)`
`s = 29.4 ms^(-1) xx 3S + (1)/(2) xx (-9.8 ms^(-2)) xx (3s)^(2)`
`s = 88.2 - 44.1 m`
`s = 44.1 m`