Home
Class 10
PHYSICS
How can three resistors of resistance 2 ...

How can three resistors of resistance 2 `Omega` 3 `Omega` and 6 `Omega` be connected to give a total resistance of (a) 4 `Omega` (b) 1 `Omega` ?

Text Solution

Verified by Experts

For `1Omega` resistance :

All these three resistances are connected in parallel to equivalent resistance of `1Omega`.
Promotional Banner

Topper's Solved these Questions

  • ELECTRICITY

    NAND LAL PUBLICATION|Exercise ACTIVITY 12.1 |6 Videos

  • ELECTRICITY

    NAND LAL PUBLICATION|Exercise ACTIVITY 12.2|2 Videos

  • LIGHT : REFLECTION AND REFRACTION

    NAND LAL PUBLICATION|Exercise ADDITIONAL QUESTIONS |7 Videos

Similar Questions

Explore conceptually related problems

How will you connect three resistors, each of resistance 6 Omega , so that the combination has a resistance of (i) 9 Omega ,(ii) 4 Omega

Three resistors 2 Omega , 4 Omega and 5 Omega are combined in parallel. What is the total resistance of the combination?

Three resistors 1 Omega , 2 Omega and 3 Omega are combined in series. What is the total resistance of the combination?

Three resistors 2Omega , 4Omega and 5Omega are combined in parallel. What is the total resistance of the combination?

Three resistors 1Omega , 2Omega and 3Omega are combined in series. What Is the total resistance of the combination?

Given the resistances of 1Omega ,2Omega ,3Omega , how will be combine them to get an equivalent resistance of (i) (11//3)Omega (ii) (11//5)Omega , (iii) 6Omega , (iv) (6//11)Omega ?