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How many 176 Omega resistors in parallel...

How many 176 `Omega` resistors in parallel are required to carry 5A on a 220 V line?

Text Solution

Verified by Experts

Let the number of resistors=n.
`:. (1)/(R )=(1)/(176)+(1)/(176)+….n` times
`R=(176)/(n)`
Now, `I=(V)/(R )`
`5=(220)/((176)/(n))`
`rArr n=(5xx 176)/(220)=4`
n =4
Number of resistors = 4
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