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An electric heater of resistance 8Omega ...

An electric heater of resistance 8`Omega` draws 15 A from service mains for 2 hour,Calculate the rate at which heat is developed in the heater.

Text Solution

Verified by Experts

Rate of heat = Power
`P=(E )/(t)=(I^(2)Rt)/(t)`
`P=I^(2)R`
`=15^(2)xx8=225 xx 8=1800` Watt
So heat is developed at the rate of 1800 J/sec.
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