F is always perpendicular to v and B in the formula `F=q( v × B )`.
is this statement true.

For all sets A and B, (A – B)∪ (A∩ B) = A. Is this statement true?

Statement I: If a is perpendicular to b and c, then axx(bxxc)=0 Statement II: if a is perpendicular to b and c, then bxxc=0

A conductor of length l is moved perpendicular to uniform magnetic field B with velocity v as shown in the figure The e.m.f. induced across the length of the conductor is

A charge q moving in a straight line is accelerated by a potential difference V. It enters a uniform magnetic field B perpendicular to its path. Deduce in terms of V an expression for the radius of the circular path in which they travel?

Let f be a differentiable function on the open interval(a, b). Which of the following statements must be true? (i) f is continuous on the closed interval [a,b], (ii) f is bounded on the open interval (a,b) (iii)If a (a)Only I and II (b)Only I and III (c)Only II and III (d)Only III

A conducting rod of length 'l' is moved in a magnetic field of magnitude B with velocity v such that the arrangement is mutually perpendicular. Prove that the e.m.f. induced in the rod is |E| = Blv .

A conducting rod of length 'l' is moved in a magnetic field of magnitude B with velocity v such that the arrangement is mutually perpendicular. Prove that the e.m.f. induced in the rod is |E| = Blv .

If a function (continuos and twice differentiable) is always concave upward in an interval, then its graph lies always below the segment joining extremities of the graph in that interval and vice-versa. Let f:R^(+)toR^(+) is such that f"(x)ge0 AAx in [a,b] . Then value of int_(a)^(b)f(x) dx cannot exceed:

Using Euler's formula find the unknown. F = 5, V = ?, E= 9

A point charge Q is placed at point O as shown in the figure. is the potential difference V_A - V_B positive, negative or zero if Q is postive or negative?