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For a gas C(P)-C(V)=R in a state P and ...

For a gas `C_(P)-C_(V)=R` in a state P and `C_(P)-C_(V)=1.10 R` in a state Q, `T_(P)` and `T_(Q)` are the temperatures in two different states P and Q respectively. Then

A

`T_(P)=T_(Q)`

B

`T_(P)ltT_(Q)`

C

`T_(P)=0.9 T_(Q)`

D

`T_(P)gtT_(Q)`

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Knowledge Check

  • The value of C_(P) - C_(v) = 1.00 R for a gas in state A and C_(P) - C_(v) = 1.06 R in another state. If P_(A) and P_(B) denote the pressure and T_(A) and T_(B) denote the temperature in the two states, then

    A
    `P_(A) = P_(B), T_(A) gt T_(B)`
    B
    `P_(A) lt P_(B), T_(A) = T_(B)`
    C
    `P_(A) lt P_(B), T_(A) gt T_(B)`
    D
    `P_(A) = P_(B), T_(A) lt T_(B)`

  • The value of (C_p - C_v) is 1.00 R for a gas sample in state A and is 1.08 R in state B. Let ( p_A, p_B) denote the pressures and (T_A and T_B) denote the temperatures of the states A and B respectively . Most likely

    A
    `p_A lt p_B` and `T_A gt T_B`
    B
    `p_A gt p_B and T_A lt T_B`
    C
    `p_A = p_B and T_A lt T_B`
    D
    `p_A gt p_B and T_A = T_B`

  • The p^(th),q^(th) and r^(th) terms of an AP are a,b and c, respectively. The value of a(q-r)+b(r-p)+c(p-q) is

    A
    1
    B
    `-1`
    C
    0
    D
    `1//2`
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