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Electrons with de-Broglie wavelength lam...

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A

0

B

`(hc)/(mc)`

C

`(2m^(2)c^(2)lambda^(2))/(h^(2))`

D

`(2m lambda^(2))/(h)`

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