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If a triangle ABC, AB = 5 units, angle B...

If a triangle ABC, AB = 5 units, `angle B = cos^(-1) ((3)/(5))` and radius of circumcircle of `Delta ABC` is 5 units, then the area (in sq. units) of `Delta ABC` is :

A

`10 + 6 sqrt(2)`

B

`8 + 2sqrt(2)`

C

`6 + 8sqrt(3)`

D

`4 + 2sqrt(3)`

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