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If the shortest distance between the straight lines `3(x-1) = 6(y-2) = 2(z-1)` and `4(x-2) = 2(y-lambda) = (z-3), lambda in R` is `(1)/(sqrt(38))`, then the integral value of `lambda` is equal to :

A

3

B

2

C

5

D

`-1`

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