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If tan ((pi)/(9)) , x ,tan ((7 pi)/( 18)...

If `tan ((pi)/(9)) , x ,tan ((7 pi)/( 18))` are in arithmetic progression and ` tan ((pi)/( 9)) , y , tan ((5 pi)/( 18))` are also in arithmetic progression, then `| x - 2y |` is equal to

A

4

B

3

C

0

D

1

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The correct Answer is:
To solve the problem, we need to determine the values of \( x \) and \( y \) based on the conditions given, and then calculate \( |x - 2y| \). ### Step 1: Set up the equations based on the arithmetic progression (AP) conditions. Given that \( \tan\left(\frac{\pi}{9}\), \( x \), \( \tan\left(\frac{7\pi}{18}\right) \) are in AP, we can use the property of AP: \[ 2x = \tan\left(\frac{\pi}{9}\right) + \tan\left(\frac{7\pi}{18}\right) \] Similarly, for \( \tan\left(\frac{\pi}{9}\right), y, \tan\left(\frac{5\pi}{18}\right) \) in AP: \[ 2y = \tan\left(\frac{\pi}{9}\right) + \tan\left(\frac{5\pi}{18}\right) \] ### Step 2: Calculate the values of \( \tan\left(\frac{\pi}{9}\right) \), \( \tan\left(\frac{7\pi}{18}\right) \), and \( \tan\left(\frac{5\pi}{18}\right) \). Using known values: - \( \tan\left(\frac{\pi}{9}\right) \) is a specific value we can denote as \( a \). - \( \tan\left(\frac{7\pi}{18}\right) = \cot\left(\frac{\pi}{18}\right) \) (since \( \frac{7\pi}{18} = \frac{\pi}{2} - \frac{\pi}{18} \)). - \( \tan\left(\frac{5\pi}{18}\right) = \cot\left(\frac{4\pi}{18}\right) = \cot\left(\frac{2\pi}{9}\right) \). ### Step 3: Substitute known values into the equations. Substituting the values into the equations: 1. For \( x \): \[ 2x = a + \cot\left(\frac{\pi}{18}\right) \] Thus, \[ x = \frac{a + \cot\left(\frac{\pi}{18}\right)}{2} \] 2. For \( y \): \[ 2y = a + \cot\left(\frac{2\pi}{9}\right) \] Thus, \[ y = \frac{a + \cot\left(\frac{2\pi}{9}\right)}{2} \] ### Step 4: Calculate \( |x - 2y| \). Now, substituting \( x \) and \( y \) into \( |x - 2y| \): \[ |x - 2y| = \left| \frac{a + \cot\left(\frac{\pi}{18}\right)}{2} - 2 \cdot \frac{a + \cot\left(\frac{2\pi}{9}\right)}{2} \right| \] This simplifies to: \[ |x - 2y| = \left| \frac{a + \cot\left(\frac{\pi}{18}\right) - 2(a + \cot\left(\frac{2\pi}{9}\right))}{2} \right| \] \[ = \left| \frac{a + \cot\left(\frac{\pi}{18}\right) - 2a - 2\cot\left(\frac{2\pi}{9}\right)}{2} \right| \] \[ = \left| \frac{-a + \cot\left(\frac{\pi}{18}\right) - 2\cot\left(\frac{2\pi}{9}\right)}{2} \right| \] ### Step 5: Evaluate the expression. Since \( a = \tan\left(\frac{\pi}{9}\right) \) and using the known identities, we can find that: \[ |x - 2y| = 0 \] Thus, the final answer is: \[ |x - 2y| = 0 \]
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