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underset(pi/3)overset(pi/2)int sqrt(1-co...

`underset(pi/3)overset(pi/2)int sqrt(1-cosx)/(1+cosx)^(5//2)dx`

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underset(pi/2)overset(pi/3)int sqrt(1+cosx)/(1-cosx)^(5//2)dx

Evaluate: underset(pi//3)overset(pi//2)int(sqrt(1+cosx))/(1-cosx)^(7//2)dx

Evaluate the following integrals: underset(pi//3)overset(pi//2)intsqrt((1+cosx))/((1-cosx)^(5//2)dx

underset0 overset(pi//2)int sqrt(1-cos2x)dx

underset(pi//6)overset(pi//2)int (cosx)/(sin(x/2)+cos(x/2))dx

underset0overset(pi//4)int sqrt(1+sin2x)dx

Evaluate the following integrals. underset(pi//2)overset(pi)inte^x(1-sinx)/(1-cosx)dx

underset(pi/6)overset(pi/3) int sqrt(cosx)/(sqrtsinx+sqrtcosx)dx =

Evaluate the following: underset(0)overset(pi//2)int(sin^2x)/((1+cosx)^2)dx

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PRADEEP PUBLICATION-INTEGRALS-EXERCISE
  1. underset(pi//6)overset(pi//2)int (cosx)/(sin(x/2)+cos(x/2))dx

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  2. underset(pi/2)overset(pi/3)int sqrt(1+cosx)/(1-cosx)^(5//2)dx

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  3. underset(pi/3)overset(pi/2)int sqrt(1-cosx)/(1+cosx)^(5//2)dx

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  4. underset(pi//6)overset(pi//2)int (cosx)/(sin(x/2)+cos(x/2))dx

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  5. underset0overset1int sin^-1((2x)/(1+x^2))dx

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  6. underset0overset(pi//2)int dx/(a^2cos^2x+b^2sin^2x)

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  7. underset0overset(pi//4)int (sin^2xcos^2x)/(sin^3x+cos^3x)^2dx

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  8. underset0overset1int (tan^-1xdx)

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  9. underset0oversetinftyint (xtan^-1x)/(1+x^2)dx

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  10. underset1overset2int (dx)/((x+1)sqrt(x^2-1))

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  11. underset0overset(1//2)int (dx)/((1+x^2)sqrt(1-x^2))

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  12. Evaluate the following integrals by changing the limits of integration...

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  13. Evaluate the following integrals by changing the limits of integration...

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  14. underset0 oversetpi int(dx)/(3+2sinx+cosx)

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  15. Evaluate: underset(0)overset(pi//2)int(sinx)/(sinx+cosx)dx

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  16. underset0oversetaint (dx)/(a^2+ax-x^2)

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  17. If underset0oversetaint sqrtx dx=2a underset0overset(pi//2)int sin^3xd...

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  18. Prove that: underset0overset(pi/4)int (sqrttanx+sqrtcotx)dx=pi/sqrt2

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  19. Prove that underset0oversetaint f(x)dx=underset0overseta int f(a-x)dx.

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  20. Prove that : underset(0)overset(2a)intf(x) dx = underset(0)overset(2a)...

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