find the area under the curve y= sqrt(3x...

find the area under the curve `y= sqrt(3x+4)` ,lying between x= 0 and x= 4.

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PRADEEP PUBLICATION-APPLICATIONS OF INTEGRALS-EXERCISE

find the area under the curve y= sqrt(3x+4) ,lying between x= 0 and x=...
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Draw rough sketch of the function y = 2sqrt(1-x^2), x in [0,1] and eva...
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Find the area enclosed between the curve y ^2= 8x and the line x= 2.
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Make a rough sketch of the functionn y= x^2, 0 lex le 3 and determine ...
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Find the area of the regionn bounded by the curve x^2= 4y, the y-axis ...
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Make a rough sketch of the graph of the function y = 4-x^2, 0 le xle 2...
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Sketch the graph of the curve y= sqrtx+ 1 in the interval [0,4] and de...
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Make a rough sketch of the curve y = 2 sin x, 0 le x le pi, and deter...
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(i) Make a rough sketch of the graph of the function y=sin x,0lexlepi/...
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Make a rough sketch of the graph of the function y = cos^2x, 0le xle p...
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Using integration find the area of the region bounded by the triangle ...
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Using integration find the area of region bounded by the triangle wher...
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Using integration find the area of region bounded by the triangle whos...
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Using integration find the area of region bounded by the triangle wher...
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Using integration find the area of the circle x^2+y^2= r^2.
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