If `vec a and vec b` are the position vectors of A and B respectively, find the position vector of a Point C in BA produced such that BC = 1.5 BA.

If veca & vecb are the position vectors of A & B respectively and C is a point on AB produced such that AC=3AB then the position vector of C is:

If a and b are position vector of two points A,B and C divides AB in ratio 2:1, then position vector of C is

Let vec a and vec b be the position vectors of the points (3,-5) and (m,4) respectively. Find m if the vectors vec a and vec b are collinear.

If vec a , vec b , vec c , vec d are the position vector of point A , B , C and D , respectively referred to the same origin O such that no three of these point are collinear and vec a + vec c = vec b + vec d , than prove that quadrilateral A B C D is a parallelogram.

If position vector of points A,B and C are respectively hati,hatj, and hatk and AB=CX , then position vector of point X is

If vec a , vec b are the position vectors of the points (1,-1),(-2,m), find the value of m for which vec aa n d vec b are collinear.

Let vec a and vec b be two unit vectors and θ is the angle between them. Then vec a+vec b is a unit vector if

If vec a and vec b are proper vectors such that vec b= λ veca for some real λ then vec a and vec b are

If the position vectors of the points A,B and C be a,b and 3a-2b respectively, then prove that the points A,B and C are collinear.