A speaks truth in 60% of the cases, while B in 90% of the cases. In what percentage are they likely to contradict each other in stating the same fact? In the case of contradiction do you think , the statement of B will carry more weight as he speaks truth in more number of case than A?

A speaks truth in 75% and B in 80% of the cases. In what percentage of cases are they likely to contradict each other in narrating the same incident?

A speaks truth in 75% of the cases. While B in 90% of the cases. In what percent of cases are they likely to contradict each other in stating in the same fact? Do you think that statement of B is true?

In a family, the husband tells in a lie in 30% cases and the wife in 35% cases. Find the probability that both contradict each other on the same fact.

The probability that A speaks truth is 4/5 while this probability for H is (3)/(4). The probability that they contradict each other when asked to speak on a fact is :

A and B are two independent witnesses (i.e., there is no collision between them) in a case. The probability that A will speak the truth is x and the probability that B will speak the truth is y. A and B agree in a certain statement. Show that the probability that the statement is true is (xy)/(1-x-y+2xy) .

Tabulate the number of faces, edges and vertices from the following polyhedrons. (Here 'V' stands for the number of vertices, 'F' stands for number of faces, and 'E' stands for number of edges). What do you inter from the last two columns? In each case, do you find F+ V= E + 2 i.e., F+ V -E=2? This relationship is called Euler's formula. In fact this formula is true for any polyhedron.