There are two independent events `E_1` and `E_2` and `P(E_1)=0.30`, `P(E_2)=0.60` find the probability that
one and only one event happens.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that both E_1 and E_2 occur.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that at least one of E_1 and E_2 happens.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that neither E_1 nor E_2 occurs.

If P(E) = 0.05, which is the probability of not E.

What will be the probability of event E + event not E ?

Ea n dF are two independent events. The probability that both Ea n dF happen is 1/12 and the probability that neither Ea n dF happens is 1/2. Then, P(E)=1//3, P(F)=1//4 P(E)=1//4, P(F)=1//3 P(E)=1//6, P(F)=1//2 P(E)=1//2, P(F)=1//6

Of the three independent events E_(1),E_(2),and E_(3), the probability that only E_(1) occurs is alpha only E_(2) occurs is beta, and only E_(3) occurs is gamma. Let the probability p that none of events E_(1),E_(2), or E_(3) occurs satisfy the equations (alpha-2beta)p=alpha betaand (beta-3gamma)p=2betagamma. All the given probabilities are assumed to lie in the interval (0,1). Then ("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=

If E and F are independent events, P (E) = 1/2 and P (F) = 1/3 , then P (E nn F) is :

If E and F are independent events, P(E) = 1/20 and P(F) = 1/3 then P (E cap F) is :