An electronic assembly consists of two subsystems, say, A and B. From previous testing procedures, the following probabilities are assumed to be known : `P(A` fails ) `= 0.2, P(`B fails alone ) `= 0.15, P(A` and B fail `) = 0.15` Evaluate the following probabilities: P(A fails alone)

An electronic assembly consists of two subsystems, say, A and B. From previous testing procedures, the following probabilities are assumed to be known : P(A fails ) = 0.2, P( B fails alone ) = 0.15, P(A and B fail ) = 0.15 Evaluate the following probabilities: P(A fails | B has failed )

Check whether the following probabilities P(A) and P(B) are consistently defined:- P(A) = 0.5, P(B) = 0.7, P(A nn B) = 0.6

Check whether the following probabilities P(A) and P(B) are consistently defined:- P(A) = 0.5, P(B) = 0.4, P(A uu B) = 0.8

Check whether the following Probabilities P (A) and P (B) are Consistently defined : P(A) =0.5, P (B)=0.7, P(A nn B) = 0.06 .

If P(A) = 0·4, P(B) = 0.2 and P(B/A) = 0·5, then P(A nn B) is :

Check whether the following Probabilities P (A) and P (B) are Consistently defined : P(A) =0.5. P (B)=0.4, P(A uu B) = 0.8 .

If P(A) = 0.8, P(B) = 0.5 and P (B|A) = 0.4 find: P(A|B)

Choose the correct answer : If P(A) = 0.8, P(B) = 0.5 P(B/A) = 0.4, find P(A nn B)

If P(A) = 0.8, P(B) = 0.5 and P (B|A) = 0.4 find: P(AcapB)

If P(A) = 1/2 , P(B) = 0, P(A//B) is :