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2 g of CaCO(3) on strong heating gave 1....

2 g of `CaCO_(3)` on strong heating gave `1.12 g` of CaO and 448 ml of `CO_2`. Show that the results illustrate the law of conservation of mass.

Text Solution

Verified by Experts

2400 ml of ` CO _(2)` weight 44 g , Therefore, mass of `448 ml CO _(2) = ( 448 m1 xx 44 g)/( 22400 ml ) = 0. 88 g `
Weights of `C a O + CO _(2) = ` Weight of `Ca CO _(3) implies 1.12 + 0.88 = 2.00 g `
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