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Nitrogen forms NO and NH3. Show that equ...

Nitrogen forms NO and `NH_3`. Show that equivalent mass is not a fixed quantity and that it varies from reaction to reaction.

Text Solution

Verified by Experts

`N _(2) ( 28 g ) + O _(2) ( 32 g ) to 2 NO implies 28` nitrogen `-=32` oxygen.
Equivalent mass of nitrogen in `NO 7 g eq ^(-1).`
`N _(2) ( 28g ) + 3 H _(2) (6g) to NH _(3) implies 28` g nitrogen `-=6g` hydrogen
Equivalent mass of nitrogen in `NH _(3) = 4 66 g eq ^(-1)`
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