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Find out the limiting reagent when 5g of...

Find out the limiting reagent when 5g of `H_2` reacts with 24g of `O_2` to form water.

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Stoichiometric ratio : ` 2 H _(2) (g) + O _(2) (g) to 2 H _(2) (l)`
`{:("Mass of reac tan ts",5g, 24 g),("Mass of reac tan ts", 2.5, 0.75):}`
Ratio of moles (H:O) needed for complete reaction `= 2:1 or 2.5 : 1.25.`
Since number of moles of `O_(2)` is less than required, `O_(2)` is the limiting reagent.
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