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What is the final molarity of a solution...

What is the final molarity of a solution of `9.8g H_(2)SO_(4)` in 250mL water when mixed with 250mL of `0.1M H_(2)SO_(4)`?

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Molarity of `H _(2) SO_(4)` solution ontaining `9.8 g ` in 250 mL water `= (9.8 xx 1000)/(98 xx 250) = 0.4`
When 250 ml of `0.4 M ` solution is mixed with 250 mL of `0.1 M ` solution
Final molarity `= (( 250 xx 0.4) + ( 250xx 0.1 ))/( 250 + 250) = 0. 25`
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