`0.5 g` of silver salt of a dibasic organic acid left a residue of `0.27` of silver on ignition. Calculate the molecular mass of the acid.

Explanation

Mass of silver salt=0.5g
Mass of Ag obtained=0.27 g
Molar mass of acid `= n (( 108 xx W)/(x) - 10 7) g mol ^(-1) = 2 (( 108 xx 0.5)/( 0.27) - 107) = 186 g mol ^(-1).`