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How many molecules are present in 5.23g ...

How many molecules are present in `5.23g` of glucose `(C_(6)H_(12)O_(6))`?

A

`1.65 xx 1 ^(22)`

B

`1.75 xx 10 ^(22)`

C

`1.75 xx 10 ^(21)`

D

`1.65 xx 10 ^(21)`

Text Solution

Verified by Experts

The correct Answer is:
B

`because 180` g glucose has `N _(A)` molecules
`therefore 5.23` g glucose has `(5.23 xx 6. 02 xx 10^(23))/(180) = 1. 75 xx 10 ^(22)` molecules
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