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What is the empirical formula of vanadiu...

What is the empirical formula of vanadium oxide, if `2.74 g` of the metal oxide contains `1.53 g` of metal ? (Atomic mass of vanadium=52 u)

A

`V _(2) O _(3)`

B

`VO`

C

`V _(2) O _(5)`

D

`V _(2) O _(7)`

Text Solution

Verified by Experts

The correct Answer is:
C
Metal oxide `= 2. 74 g ,% or V = ( 1. 53)/(2. 74) xx 100 = 55. 83`
Thus, `% of O = 100 - 55. 83 = 44. 17`
No. of moles of `V = (55. 83)/( 53) = 1.1 ` No. of moles of `O = ( 44. 17)/(16) =2. 76`
Simpliest ratio of V and O `= 1. 2.5 or 2: 5` Hence, the empirical formula `= V _(2) O _(5)`
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