In the reaction `4NH_(3)(g)+5O_(2)(g) to 4NO(g)+6H_(2)O(l)`, when 1 mole of ammonia and 1 mole of `O_2` are made to react to completion.

Options

A. 1.0 mole of `H_(2)O` is produced
B. 1.0 mole of NO will be produced
C. All the oxygen will be consumed
D. All the ammonia will be consumed

Answer

C

Explanation

`underset("1 mol")(4 NH _(3 (g))) + underset("1 mol")( 5O _(2(g)))to 4 NO _((g)) = 6 H _(2) O _((l))`
`O _(2)` Is the limiting reactant `therefore 0.8` mol 1 NO is produced, 1.2 mol `H _(2) O` is produced All the `O_(2)` will be consumed and `0.2` mol `NH_(3)` will be left.