If one gram of a metal carbonate gave `0.56g` of its oxide on heating, then equivalent weight of the metal will be

Options

A. 30
B. 40
C. 25
D. 20

Answer

B

Explanation

g eq. metal carbonate = g eq. of metal oxide, `(1.0)/(M + 60) = (0.56)/(M + 16)`
where M = at wt. of metal M. Solving for M gives `M = 40`
The equivalent weight of metal M is `(40)/(2) = 20.`